Enderton. Peano systems.
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@ -419,6 +419,25 @@ A \textbf{partition} $\Pi$ of a set $A$ is a set of nonempty subsets of $A$ that
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\end{definition}
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\section{\defined{Peano System}}%
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\hyperlabel{ref:peano-system}
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A \textbf{Peano system} is a triple $\langle N, S, e \rangle$ consisting of a
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set $N$, a function $S \colon N \rightarrow N$, and a member $e \in N$ such
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that the following three conditions are met:
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\begin{enumerate}[(i)]
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\item $e \not\in \ran{S}$.
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\item $S$ is one-to-one.
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\item Every subset $A$ of $N$ containing $e$ and closed under $S$ is $N$
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itself.
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\end{enumerate}
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\begin{definition}
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\lean*{Common/Set/Peano}{Peano.System}
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\end{definition}
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\section{\defined{Power Set}}%
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\hyperlabel{ref:power-set}
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@ -6015,11 +6034,52 @@ Show that $<_L$ is a linear ordering on $A \times B$.
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\end{proof}
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\section{Peano's Postulates}%
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\hyperlabel{sec:peanos-postulates}
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\subsection{\verified{Theorem 4D}}%
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\hyperlabel{sub:theorem-4d}
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\begin{theorem}[4D]
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$\langle \omega, \sigma, 0 \rangle$ is a Peano system.
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\end{theorem}
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\begin{proof}
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\lean{Common/Set/Peano}{Peano.instSystemNatUnivSuccOfNatInstOfNatNat}
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Note $\sigma$ is defined as $\sigma = \{\pair{n, n^+} \mid n \in \omega\}$.
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To prove $\langle \omega, \sigma, 0 \rangle$ is a \nameref{ref:peano-system},
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we must show that (i) $0 \not\in \ran{S}$, (ii) $\sigma$ is one-to-one, and
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(iii) every subset $A$ of $\omega$ containing $0$ and closed under $\sigma$
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is $\omega$ itself.
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\paragraph{(i)}%
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This follows immediately from \nameref{sub:theorem-4c}.
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\paragraph{(ii)}%
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Let $n^+ \in \ran{\sigma}$.
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By construction, there exists some $m_1 \in \omega$ such that $m_1 = n^+$.
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Suppose there exists some $m_2 \in \omega$ such that $m_2 = n^+$.
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By definition of the \nameref{ref:successor}, $m_1 = n \cup \{n\} = m_2$.
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By the \nameref{ref:extensionality-axiom}, $m_1 = m_2$.
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Thus $\sigma$ is one-to-one.
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\paragraph{(iii)}%
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This follows immediately from \nameref{sub:theorem-4b}.
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\end{proof}
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\section{Exercises 4}%
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\hyperlabel{sec:exercises-4}
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\subsection{\verified{Exercise 4.1}}%
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\label{sub:exercise-4.1}
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\hyperlabel{sub:exercise-4.1}
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Show that $1 \neq 3$ i.e., that $\emptyset^+ \neq \emptyset^{+++}$.
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@ -1,3 +1,4 @@
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import Common.Set.Basic
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import Common.Set.Interval
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import Common.Set.Partition
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import Common.Set.Partition
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import Common.Set.Peano
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@ -1,8 +1,6 @@
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import Mathlib.Data.Real.Basic
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import Mathlib.Data.Set.Intervals.Basic
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import Common.List.Basic
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/-! # Common.Set.Interval
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A representation of a range of values.
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@ -1,7 +1,3 @@
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import Mathlib.Data.Finset.Basic
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import Mathlib.Data.List.Sort
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import Mathlib.Data.Set.Intervals.Basic
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import Common.List.Basic
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import Common.List.NonEmpty
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import Common.Set.Interval
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@ -0,0 +1,42 @@
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import Mathlib.Data.Rel
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import Mathlib.Data.Set.Basic
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/-! # Common.Set.Peano
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Data types and theorems used to define Peano systems.
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-/
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namespace Peano
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/--
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A `Peano system` is a triple `⟨N, S, e⟩` consisting of a set `N`, a function
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`S : N → N`, and a member `e ∈ N` such that the following three conditions are
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met:
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1. `e ∉ ran S`.
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2. `S` is one-to-one.
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3. Every subset `A` of `N` containing `e` and closed under `S` is `N` itself.
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-/
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class System (N : Set α) (S : α → α) (e : α) where
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zero_range : e ∉ Set.range S
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injective : Function.Injective S
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induction : ∀ A, A ⊆ N ∧ e ∈ A ∧ (∀ a ∈ A, S a ∈ A) → A = N
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instance : System (N := @Set.univ ℕ) (S := Nat.succ) (e := 0) where
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zero_range := by
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simp
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injective := by
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intro x₁ x₂ h
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injection h
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induction := by
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intro A h
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suffices Set.univ ⊆ A from Set.Subset.antisymm h.left this
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show ∀ n, n ∈ Set.univ → n ∈ A
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intro n hn
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induction n with
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| zero => exact h.right.left
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| succ n ih =>
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refine h.right.right n (ih ?_)
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simp
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end Peano
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